2x^2+3xy+4y^2=20

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Solution for 2x^2+3xy+4y^2=20 equation: 


Simplifying
2x2 + 3xy + 4y2 = 20

Reorder the terms:
3xy + 2x2 + 4y2 = 20

Solving
3xy + 2x2 + 4y2 = 20

Solving for variable 'x'.

Reorder the terms:
-20 + 3xy + 2x2 + 4y2 = 20 + -20

Combine like terms: 20 + -20 = 0
-20 + 3xy + 2x2 + 4y2 = 0

The solution to this equation could not be determined.

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